Evaluating the composition of Functions

The video tutorial explains how to solve the composition of the tangent of the sine inverse of sqrt 3/2. It begins by evaluating the inverse sine of sqrt 3/2, identifying the angle within the range of -π/2 to π/2, which is π/3. The tutorial then demonstrates how to calculate the tangent of π/3, resulting in a final solution of sqrt 3. The process highlights the steps involved in evaluating compositions of trigonometric and inverse functions.

What is the first step in evaluating the composition of tangent of sine inverse?

How do you determine the angle Theta when the sine of Theta equals sqrt 3 / 2?

What angle corresponds to the sine value of sqrt 3 / 2?

What is the tangent of the angle π / 3?

What is the final solution when simplifying the tangent of π / 3?