Solving trigonometric equations with multiple angles

The video tutorial explains how to solve sine equations, specifically when sine of 2X equals -sqrt(3)/2. It begins by identifying angles on the unit circle where sine equals -sqrt(3)/2, then addresses solving for 2X instead of X. The tutorial continues by finding all solutions using coterminal angles and concludes with the final solution for X.

What is the first step to find the solutions for the sine of an angle equal to negative sqrt(3)/2?

How do you determine the angles on the unit circle where the sine is equal to negative sqrt(3)/2?

What are the two angles found in the interval of 0 and 2π for which the sine is equal to negative sqrt(3)/2?

Explain how to find all solutions for the sine being negative sqrt(3)/2 beyond the interval of 0 and 2π.

What is the final solution for X after dividing by two, and how is it expressed?