Modeling Parabolic Equations in Context

Modeling Parabolic Equations in Context

Assessment

Interactive Video

Mathematics, Architecture

9th - 12th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to mathematically model an arched bridge using a second-degree polynomial equation. It introduces the concept of using zeros of a graph to find the equation and demonstrates this through Kevin's assignment, where he models a bridge as a parabola. Kevin uses the stream as the x-axis and calculates the x-intercepts and vertex to derive the equation. Maria's approach is also discussed, showing how different placements of the parabola can lead to different equations but the same leading coefficient. The tutorial concludes by comparing the shapes of parabolas to real-world problems, emphasizing the importance of understanding the relationship between the graph and the physical structure.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of using the zeros of a graph in modeling a parabolic equation?

To identify the slope of the parabola

To determine the x-intercepts of the parabola

To find the maximum height of the parabola

To calculate the area under the parabola

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In Kevin's example, what are the x-intercepts of the arched bridge?

10 and 20

0 and 10

0 and 20

5 and 15

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where is the vertex of the parabola in Kevin's arched bridge example?

(0, 10)

(10, 0)

(20, 10)

(10, 10)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How did Kevin determine the factored form of the quadratic equation?

By calculating the slope of the parabola

By using the zeros of the equation

By using the vertex coordinates

By measuring the height of the arch

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What was the final equation Kevin found for the arched bridge?

y = -1/10 x^2 + 2x

y = -x^2 + 20x

y = x^2 - 20x

y = 1/10 x^2 - 2x

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How did Maria's approach differ from Kevin's in modeling the bridge?

She used a different height for the arch

She placed the vertex on the y-axis

She used a different width for the stream

She calculated a different slope

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why did Maria and Kevin have the same leading coefficient in their equations?

Because they used the same x-intercepts

Because they measured the same height

Because the shape of the parabola was the same

Because they used the same vertex

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