
Completing the Square Concepts
Interactive Video
•
Mathematics
•
9th - 10th Grade
•
Practice Problem
•
Hard
Lucas Foster
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the primary purpose of completing the square in relation to quadratic equations?
To find the roots of a linear equation
To simplify a quadratic equation into a linear one
To transform a quadratic equation into a perfect square form
To eliminate the constant term in a quadratic equation
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in setting up a quadratic equation for completing the square?
Subtracting the constant term from both sides
Adding a constant to both sides
Multiplying both sides by the coefficient of x
Dividing both sides by the constant term
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it important to have a coefficient of 1 for the x squared term when completing the square?
It simplifies the process of finding the roots
It allows for easier factoring of the equation
It makes the equation easier to graph
It ensures the equation is in standard form
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What do you add to both sides of the equation to complete the square?
The square of the coefficient of x
Half of the coefficient of x
The coefficient of x divided by 2
The square of half the coefficient of x
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of taking the square root of both sides of the equation after completing the square?
A simplified radical expression
A linear equation
A binomial expression
A quadratic equation
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the plus or minus sign when taking the square root of both sides?
It indicates the equation has no solution
It shows there are two possible solutions
It simplifies the equation to a single solution
It eliminates the need for further calculation
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final form of the quadratic formula derived from completing the square?
x = b ± √(b² - 4ac) / 2a
x = -b ± √(b² - 4ac) / 2a
x = -b ± √(b² + 4ac) / 2a
x = b ± √(b² + 4ac) / 2a
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