

Analyzing Rate Laws and Reaction Mechanisms in Chemical Reactions
Interactive Video
•
Chemistry, Science, Biology
•
11th - 12th Grade
•
Practice Problem
•
Hard
Patricia Brown
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What was determined about the rate law in the initial analysis?
It is zeroth order with respect to NO2.
It is second order with respect to NO2.
It is third order with respect to NO2.
It is first order with respect to NO2.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does a linear graph of 1 over the concentration of NO2 indicate?
Third order reaction
First order reaction
Second order reaction
Zeroth order reaction
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the context of reaction mechanisms, what is an intermediate?
A substance that is a reactant in the first step and a product in the last step
A catalyst that speeds up the reaction
A product that is formed at the end of the reaction
A substance that is produced and consumed during the reaction
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can't intermediates be included in rate laws?
They are only present in the final step
They are not part of the original reactants
Their concentrations are difficult to measure
They do not affect the reaction rate
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of the steady state approximation?
To determine the overall reaction order
To eliminate intermediates from the rate law
To identify catalysts in the reaction
To simplify the calculation of equilibrium constants
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the rate of the forward reaction related to the rate of the reverse reaction at equilibrium?
The forward rate is independent of the reverse rate
The forward rate is less than the reverse rate
The forward rate is greater than the reverse rate
The forward rate is equal to the reverse rate
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of combining constants in the rate law derivation?
The rate law becomes invalid
A new variable is introduced
The constants are eliminated
A single combined constant is formed
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