What does a curved position vs. time graph indicate about the motion of an object?

Translating Kinematic Graphs: Analyzing Position Velocity and Acceleration Relationships

Interactive Video
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Physics, Mathematics, Science
•
9th - 12th Grade
•
Hard

Patricia Brown
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The object is decelerating.
The object is accelerating.
The object is moving at a constant speed.
The object is stationary.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the first example, why is the velocity vs. time graph drawn in the negative region?
Because the object is moving upwards.
Because the object is moving downwards.
Because the object is stationary.
Because the object is moving at a constant speed.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the second example, what does a straight line in the positive region of a velocity vs. time graph indicate?
The velocity is changing.
The object is speeding up.
The velocity is constant.
The object is slowing down.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you represent an object slowing down on a velocity vs. time graph?
By drawing a vertical line.
By drawing a line moving away from zero.
By drawing a line moving towards zero.
By drawing a horizontal line.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the third example, what does a velocity vs. time graph with all positive values indicate?
The object is moving in the positive direction.
The object is moving at a constant speed.
The object is stationary.
The object is moving in the negative direction.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does a flattening slope on a position vs. time graph indicate about the object's motion?
The object is stationary.
The object is slowing down.
The object is moving at a constant speed.
The object is speeding up.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the fourth example, how is a graph with both negative and positive velocities treated?
As a single problem.
As two separate problems.
As a constant velocity problem.
As a stationary object problem.
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