Redox Reactions and Titration Concepts

Redox Reactions and Titration Concepts

Assessment

Interactive Video

Chemistry, Science, Mathematics

11th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers titration calculations for class 12, focusing on redox titrations involving KMnO4, more salt, and oxalic acid. It explains the components of redox titration, including oxidizing and reducing agents, and provides details on the molar mass of substances involved. The tutorial also covers balancing redox reactions and applying formulas to calculate molarity and strength of KMnO4. Practical examples and exercises are included to enhance understanding.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary focus of today's class?

Organic chemistry

Titration calculations

Mathematical equations

Physics experiments

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which substance acts as the oxidizing agent in class 12 redox titrations?

More salt

KMnO4

Oxalic acid

H2SO4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of more salt?

126 grams per mole

153 grams per mole

392 grams per mole

250 grams per mole

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the redox reaction, what is the role of dilute sulfuric acid?

It provides an acidic medium

It is the primary reactant

It neutralizes the solution

It acts as a reducing agent

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many electrons are involved in balancing the charge in the redox reaction?

Three electrons

Four electrons

Five electrons

Six electrons

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the ratio of moles of KMnO4 to moles of more salt in the reaction?

1:3

1:1

1:5

1:2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is molarity related to moles and volume?

Molarity is the ratio of moles to volume

Molarity is the difference between moles and volume

Molarity is the product of moles and volume

Molarity is the sum of moles and volume

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