Heats of Formation in Reactions

Heats of Formation in Reactions

Assessment

Interactive Video

Chemistry, Physics, Science

11th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to use heats of formation to calculate the heat of reaction. It provides a step-by-step example where the heat of reaction and heats of formation for CO2 and H2O are given, and the goal is to find the heat of formation for liquid C6H6. The process involves using stoichiometric coefficients and simplifying the equation to solve for the unknown heat of formation, resulting in a value of 48.6 kJ/mol.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary use of heats of formation in chemistry?

To find the boiling point of a liquid

To determine the color of a compound

To measure the density of a substance

To calculate the heat of reaction

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the heat of reaction calculated?

By dividing the heats of formation of products by reactants

By multiplying the heats of formation of reactants and products

By summing the heats of formation of products and reactants

By subtracting the sum of heats of formation of reactants from products

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the given example, which substances' heats of formation are provided?

C6H6 and CO2

CO2 and H2O

H2O and O2

C6H6 and O2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the stoichiometric coefficient for CO2 in the example problem?

6

2

12

0

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the heat of formation of oxygen not included in the calculation?

Because it is a gas

Because it is in its most stable form

Because it is a reactant

Because it is a product

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final calculated heat of formation for liquid C6H6?

12 kJ/mol

100 kJ/mol

0 kJ/mol

48.6 kJ/mol

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are the units in kJ instead of kJ/mol in the final calculation?

Because the reaction is exothermic

Because the heats of formation are multiplied by moles

Because the reaction is endothermic

Because the stoichiometric coefficients are ignored