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H+ Concentration and pH Calculations

H+ Concentration and pH Calculations

Assessment

Interactive Video

Chemistry, Science, Mathematics

11th - 12th Grade

Practice Problem

Hard

Created by

Patricia Brown

FREE Resource

This video tutorial explains how to calculate the pH of a 10^-6 M HCL solution when diluted 100 times. It covers the importance of considering H+ ions from both HCL and water, especially when the concentration decreases. The common ion effect is discussed, which affects the ion production from water. The tutorial walks through the calculation of total H+ concentration and the final pH, emphasizing the need to select an answer slightly greater than 6.9 due to the common ion effect.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial concentration of HCl before dilution?

10^-7 M

10^-8 M

10^-6 M

10^-5 M

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can the H+ from water be ignored initially?

Because it is too high

Because it is negligible compared to HCl

Because it is not present

Because it is equal to HCl

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the H+ concentration from water as the HCl concentration decreases?

It becomes more significant

It disappears

It remains the same

It decreases

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the concentration of H+ from diluted HCl after considering dilution?

10^-7 M

10^-6 M

10^-5 M

10^-8 M

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the common ion effect?

It has no effect on ion production

It only affects strong acids

It decreases ion production from the weaker source

It increases ion production

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total H+ concentration after considering both sources?

11 x 10^-8 M

10 x 10^-8 M

12 x 10^-8 M

9 x 10^-8 M

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the pH calculated from the total H+ concentration?

By dividing the concentrations

Using the formula pH = -log[H+]

By multiplying the concentrations

By adding the concentrations

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