Integration Techniques and Trigonometric Identities

Integration Techniques and Trigonometric Identities

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers solving integrals using trigonometric transformations, focusing on conditions for tangent and secant exponents. It provides detailed steps for solving integrals with even secant and odd tangent exponents, using identities and u-substitution. The tutorial concludes with a final example, summarizing the techniques discussed.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the conditions for the exponents of tangent and secant functions in trigonometric integration?

Both exponents should be odd

Tangent exponent should be odd, secant exponent should be even

Both exponents should be even

Tangent exponent should be even, secant exponent should be odd

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When the exponent of secant is even, which identity is used to simplify the integral?

tan^2(x) = 1 + sec^2(x)

tan^2(x) = sec^2(x) - 1

sec^2(x) = 1 - tan^2(x)

sec^2(x) = tan^2(x) + 1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the process of solving integrals, what is the purpose of using the SMS method?

To simplify the integral

To expand the equation

To find the derivative

To integrate directly

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is used when the exponent of tangent is odd?

u = cos(x)

u = sin(x)

u = tan(x)

u = sec(x)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the integral of u^n du expressed in terms of n?

u^(n+1)/(n+1)

u^(n+2)/(n+2)

u^(n-1)/(n-1)

u^n/n

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final step in solving an integral using u-substitution?

Multiply by the derivative of u

Differentiate the result

Divide by the original function

Add a constant of integration

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the final example, why is it preferred to work on the smaller exponent?

It simplifies the calculation

It avoids complex numbers

It is a standard rule

It reduces the number of steps

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