Kinematics of Free Falling Objects

This video tutorial explores a vertical free fall problem where a rock is launched from a height of 2 meters with an initial velocity of 45 m/s. The video uses a coordinate system with the origin at ground level and positive direction upwards. It demonstrates how to calculate the height and velocity of the rock after 3 seconds using kinematic equations. The tutorial concludes with an invitation to explore more physics and math resources.

What is the initial height of the rock in the vertical free fall problem?

• 3 meters

• 1 meter

• 0 meters

• 2 meters

Which direction is considered positive in the coordinate system used in the problem?

• Downward

• Upward

• Leftward

• Rightward

What is the initial velocity of the rock?

• 30 meters per second

• 45 meters per second

• 60 meters per second

• 75 meters per second

Which kinematics equation is used to calculate the height of the rock?

• v = u + at

• s = vt - 1/2 at^2

• s = ut + 1/2 at^2

• v^2 = u^2 + 2as

What is the height of the rock after three seconds?

• 92.9 meters

• 82.3 meters

• 72.5 meters

• 102.1 meters

Which kinematics equation is used to calculate the velocity of the rock?

• v = u + at

• s = ut + 1/2 at^2

• s = vt - 1/2 at^2

• v^2 = u^2 + 2as

What is the acceleration due to gravity used in the calculations?

• 10.8 m/s²

• 9.8 m/s²

• 8.9 m/s²

• 11.8 m/s²

What is the velocity of the rock after three seconds?

• 12.6 meters per second

• 10.6 meters per second

• 15.6 meters per second

• 18.6 meters per second

After three seconds, in which direction is the rock moving?

• Downward

• Upward

• Sideways

• Stationary

What should you do if you have questions about the video content?

• Leave a comment

• Search online

• Ignore them

• Ask a friend