Understanding pH and Acids

Understanding pH and Acids

Assessment

Interactive Video

Chemistry, Science, Mathematics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

This video tutorial covers problems related to pH and pOH of acidic and basic solutions. It includes three examples: calculating the pH of a 0.01 M hydrochloric acid solution, determining the hydrogen ion concentration in a solution with pH 5.50, and finding the hydrogen ion concentration in a 0.15 M acetic acid solution. The video concludes with a call to action to like, comment, and subscribe.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary focus of the video?

Exploring the periodic table

Understanding chemical reactions

Solving pH and pOH problems

Learning about organic chemistry

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the pH of a 0.01 M hydrochloric acid solution?

By adding the molarity to the pH scale

By dividing the molarity by the pH scale

By taking the negative logarithm of the hydrogen ion concentration

By multiplying the molarity by 10

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the pH of a 0.01 M hydrochloric acid solution?

3

4

2

1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can you find the hydrogen ion concentration from a pH of 5.50?

By multiplying the pH by 10

By using the formula 10 raised to the power of negative pH

By adding 5.50 to the pH scale

By dividing the pH by 10

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the hydrogen ion concentration for a solution with a pH of 5.50?

3.2 x 10^-6 M

5.5 x 10^-5 M

1.0 x 10^-5 M

2.5 x 10^-6 M

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What percentage of acetic acid is dissociated in the solution?

0.5%

1.3%

2.0%

3.5%

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the hydrogen ion concentration in a 0.15 M acetic acid solution?

By subtracting the dissociation percentage from the molarity

By multiplying the molarity by the dissociation percentage

By dividing the molarity by the dissociation percentage

By adding the dissociation percentage to the molarity

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