Stoichiometry and Molar Volume Concepts

Stoichiometry and Molar Volume Concepts

Assessment

Interactive Video

Chemistry, Science, Mathematics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers a stoichiometry problem involving the calculation of CO2 volume at STP when 23 grams of carbon monoxide are oxidized. It begins with a balanced chemical equation and proceeds to convert the given mass of CO to moles. The tutorial then uses mole ratios from the balanced equation to find the moles of CO2. Finally, it calculates the volume of CO2 at STP using the molar volume of a gas.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a stoichiometry problem?

Calculate the number of moles of products

Find the molar mass of the reactants

Write and balance the chemical equation

Convert mass to volume

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert grams of a substance to moles?

Subtract the atomic numbers

Add the atomic numbers

Divide by the molar mass

Multiply by the molar mass

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of carbon monoxide (CO)?

44.0 g/mol

12.01 g/mol

28.1 g/mol

16.0 g/mol

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the balanced equation, what is the mole ratio of CO to CO2?

2:2

1:1

2:1

1:2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of using the mole ratio in stoichiometry?

To calculate the temperature of the reaction

To determine the volume of gases

To convert moles of one substance to moles of another

To find the mass of reactants

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the volume of one mole of any gas at STP?

24.0 L

22.4 L

20.0 L

18.4 L

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to ensure conditions are at STP when using molar volume?

Because molar volume changes with temperature and pressure

To balance the chemical equation

To ensure the reaction is complete

To calculate the mass of the products

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