Constant Rate Problems and Equations

Constant Rate Problems and Equations

Assessment

Interactive Video

Mathematics

6th - 8th Grade

Hard

Created by

Thomas White

FREE Resource

This video lesson covers the concept of constant rate in eighth grade Eureka Math. It includes two examples: Pauline mowing a lawn and water flowing from a faucet, demonstrating how to solve problems using constant rate equations. The lesson also provides exercises for practice, a summary of key points, and instructions for homework.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a constant rate?

A rate that remains the same over time

A rate that changes over time

A rate that increases over time

A rate that decreases over time

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example of Pauline mowing a lawn, what is the constant rate of mowing?

2.5 square feet per minute

35 square feet per minute

14 square feet per minute

10 square feet per minute

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you solve for the unknown in a constant rate equation?

By using the multiplication property of equality

By dividing the numerators

By subtracting the numerators

By adding the denominators

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the water flow example, what is the equation used to find the volume of water?

v = 2.5t

v = 10.5t

v = 5t

v = 3.5t

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are linear equations useful in constant rate problems?

They are only applicable to non-linear problems

They provide solutions for multiple time intervals

They require complex calculations

They can only solve for one specific time

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation used to determine the number of pages typed over time in the first section?

p = 7/2 t

p = 5/2 t

p = 2/7 t

p = 3/5 t

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of Emily's painting, what is the linear equation that represents the area she can paint over time?

a = 12/5 t

a = 32/5 t

a = 5/32 t

a = 5/12 t

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