Understanding Constant of Proportionality

Understanding Constant of Proportionality

Assessment

Interactive Video

Mathematics

6th - 7th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial covers interpreting graphs of proportional relationships through various examples. It starts with a streaming service example to explain cost per month, followed by a granola mix example to illustrate the relationship between almonds and oats. The tutorial then explores the concept of proportionality in making friendship bracelets, focusing on knots per row. Finally, it provides guidance on writing equations for proportional relationships, emphasizing the importance of the constant of proportionality.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the constant of proportionality in the streaming service example?

$6.99

$8.99

$7.99

$5.99

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the total cost for a given number of months in the streaming service example?

Subtract $7.99 from the number of months

Divide the number of months by $7.99

Add $7.99 to the number of months

Multiply the number of months by $7.99

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the granola mix example, what is the constant of proportionality?

20 grams per cup

25 grams per cup

30 grams per cup

15 grams per cup

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many grams of almonds are needed for 2 cups of oats in the granola mix example?

70 grams

60 grams

50 grams

40 grams

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the constant of proportionality in the friendship bracelet example?

3 knots per row

5 knots per row

6 knots per row

4 knots per row

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If you have 12 rows in the friendship bracelet example, how many total knots will there be?

50 knots

60 knots

80 knots

70 knots

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation form is used to represent proportional relationships?

y = mx + b

y = kx

y = x/k

y = x + k

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