Animal Count and Leg Calculations

Animal Count and Leg Calculations

Assessment

Interactive Video

Mathematics

6th - 8th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explores a classic problem involving cows and chickens, focusing on solving a system of linear equations to find the number of each animal given a total number of legs. It covers setting up equations, solving them algebraically, and visualizing the solution graphically. The tutorial also delves into extensions of the problem, exploring different scenarios and providing a deeper understanding of the concepts involved.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of legs on the farm if there are 35 chickens?

100 legs

82 legs

70 legs

90 legs

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the graphical representation, what does the intersection point of the two lines represent?

The number of cows

The solution to the system of equations

The number of chickens

The total number of animals

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many chickens are there if the number of cows is zero and the total number of legs is 82?

41 chickens

30 chickens

50 chickens

20 chickens

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the slope of the line representing the relationship between cows and chickens in the problem?

Negative one-half

Positive one

Negative one

Positive one-half

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When moving from 24 animals to 30 animals while keeping the number of legs constant, how many chickens are added?

6 chickens

12 chickens

18 chickens

24 chickens

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial approach to solve the problem of reducing animals while increasing legs?

Change the number of animals first, then the legs

Change the number of legs first, then the animals

Keep both animals and legs constant

Change both animals and legs simultaneously

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the algebraic solution, what is the equation used for the number of animals?

x + y = 30

2x + 4y = 100

x + y = 36

2x + 4y = 82

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