Calculating Area of Complex Shapes

Calculating Area of Complex Shapes

Assessment

Interactive Video

Mathematics

6th - 7th Grade

Hard

Created by

Patricia Brown

FREE Resource

Steve Jones explains how to calculate the area of two-dimensional figures by dividing them into basic shapes like triangles, circles, and rectangles. He discusses the formulas for these shapes and demonstrates how to apply them to complex figures by dividing them into simpler components. The video emphasizes understanding the division of shapes and combining their areas to find the total area.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main challenge in calculating the area of irregular 2D shapes?

They have no defined boundaries.

There is no simple formula for them.

They require complex mathematical tools.

They are not two-dimensional.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which formula is used to calculate the area of a triangle?

Half the base times the height

Width times length

Pi times radius squared

Base times height

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the area of a circle?

Pi times radius squared

Half the base times the height

Width times length

Base times height

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How can complex shapes be simplified for area calculation?

By using a computer program

By estimating their perimeter

By dividing them into basic shapes

By using advanced calculus

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What basic shapes are used to simplify complex shapes?

Triangles, circles, and squares

Triangles, rectangles, and circles

Triangles, squares, and hexagons

Squares, rectangles, and circles

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example given, how is the first complex shape divided?

Into a circle and a square

Into two triangles

Into two circles

Into a triangle and a rectangle

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of dividing a shape into two rectangles?

The area is halved

The area is doubled

The area remains the same

The area becomes zero

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