Effects of Resistor Removal in Circuits

Effects of Resistor Removal in Circuits

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explores what makes a single light bulb in a circuit brighter. It emphasizes the relationship between power and brightness, explaining that a bulb with higher power will be brighter. The tutorial also examines the effect of removing a resistor from the circuit, showing that this increases the current and voltage across the bulb, thus increasing its brightness. Through calculations, the video demonstrates how power is calculated and concludes that removing a resistor results in a brighter bulb.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary focus when discussing the brightness of a light bulb in this video?

Comparing two different bulbs

A single bulb in a circuit

The shape of the bulb

The color of the bulb

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What determines the brightness of a light bulb according to the video?

The brand of the bulb

The color of the bulb

The power of the bulb

The size of the bulb

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How does removing a resistor affect the brightness of a bulb in a circuit?

It decreases the brightness

It has no effect

It increases the brightness

It changes the color of the light

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the current in the circuit when a resistor is removed?

The current fluctuates

The current decreases

The current remains the same

The current increases

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the voltage across the bulb after removing the resistor?

8 volts

4 volts

6 volts

2 volts

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the power of the bulb after the resistor is removed?

12 watts

4 watts

6 watts

9 watts

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What formula is used to calculate the power of a light bulb?

P = IR

P = I^2R

P = IV

P = V/R

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