Electrolysis and Lead Deposition Concepts

Studying the periodic table

Solving an electrolysis problem using Faraday's laws

Understanding chemical bonding

Learning about organic chemistry

Q = m * v

Q = i * t

Q = c * v

Q = p * t

Joule

Volt

Watt

Coulomb

Divide the quantity of electricity by the molar mass

Multiply the quantity of electricity by Faraday's constant

Divide the quantity of electricity by Faraday's constant

Add the quantity of electricity to Faraday's constant

100000 C/mol

96500 C/mol

100000 J/mol

96500 J/mol

Reduction of bromide ions

Oxidation of bromide ions

Oxidation of lead ions

Reduction of lead ions

2:1

1:2

1:1

2:2

By multiplying the amount of electrons by the molar mass

By adding the amount of electrons to the molar mass

By dividing the amount of electrons by the molar mass

By using the mole ratio and the amount of electrons

205 g/mol

210 g/mol

200 g/mol

207 g/mol

3.9 grams

3.8 grams

3.5 grams

4.0 grams