Metric and Imperial Unit Conversions

Metric and Imperial Unit Conversions

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

This video tutorial by Dr. Oz covers the differences between metric and imperial units, emphasizing the simplicity of metric units due to their base-10 system. It explains common conversions between the two systems, such as kilometers to miles and liters to gallons. The video includes practical examples and problem-solving exercises, demonstrating how to convert units in real-life scenarios. It also covers a speed, distance, and time problem, illustrating the application of conversions in solving such problems.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a key characteristic of metric units?

They are based on powers of 5.

They are based on random numbers.

They are based on powers of 12.

They are based on powers of 10.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a common conversion between metric and imperial units?

1 foot is 30 centimeters.

1 kilometer is 100 meters.

1 liter is 2.2 gallons.

1 mile is 1.2 kilometers.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many liters are approximately equal to 1 gallon?

6.5 liters

4.5 liters

3.5 liters

5.5 liters

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If you have 6 pints of milk, how many liters is that approximately?

3.43 liters

4.43 liters

5.43 liters

2.43 liters

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the conversion factor from pints to liters?

Multiply by 2.2

Multiply by 1.75

Divide by 1.75

Divide by 2.2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the speed, distance, and time problem, how many kilometers are equivalent to 30 miles?

48 kilometers

68 kilometers

58 kilometers

38 kilometers

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula to calculate time in a speed, distance, and time problem?

Time = Speed / Distance

Time = Distance / Speed

Time = Speed x Distance

Time = Distance x Speed

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