Heat Transfer and Phase Changes

Heat Transfer and Phase Changes

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The lecture covers the use of power in heat equations, explaining how power is a change in energy over time. It provides three examples: melting ice, heating water, and evaporating water, demonstrating how to calculate time and power using heat equations. The examples involve using specific heat and latent heat values to determine the time required for phase changes and temperature changes in materials.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the relationship between power and heat in the context of heat equations?

Power is the product of heat and time.

Power is unrelated to heat and time.

Power is the difference between heat and time.

Power is the ratio of heat to time.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first example, what is the latent heat of fusion for water used to calculate the time to melt ice?

1.0 x 10^5 J/kg

4.2 x 10^3 J/kg

3.3 x 10^5 J/kg

2.3 x 10^6 J/kg

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How long does it take to melt 10 kg of ice at its melting point with a 5000-watt power supply?

860 seconds

760 seconds

560 seconds

660 seconds

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the specific heat capacity of water used in the second example?

4.2 x 10^3 J/kg°C

2.3 x 10^6 J/kg°C

3.3 x 10^5 J/kg°C

1.0 x 10^5 J/kg°C

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How much power is required to heat 20 kg of water from 10°C to 30°C in 5 minutes?

7600 watts

6600 watts

5600 watts

4600 watts

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the third example, what is the boiling point of water used in the calculations?

80°C

90°C

100°C

110°C

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the latent heat of vaporization for water used in the third example?

2.3 x 10^6 J/kg

3.3 x 10^5 J/kg

4.2 x 10^3 J/kg

1.0 x 10^5 J/kg

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