Resistor Networks and Equivalent Resistance

Resistor Networks and Equivalent Resistance

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial covers the analysis and simplification of complex resistor networks. It begins with an introduction to series and parallel resistor combinations, followed by setting up a problem to find the equivalent resistance between two terminals. The tutorial then delves into analyzing the network, simplifying series and parallel combinations, and calculating the final equivalent resistance. A homework problem is provided for further practice.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a complex resistor network?

Start from the middle of the network

Begin from the extreme end

Calculate the total voltage

Identify all parallel resistors

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the given problem, which two resistors are initially identified as being in series?

3 ohm and 6 ohm

1 ohm and 5 ohm

4 ohm and 12 ohm

10 ohm and 2 ohm

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are the 3 ohm and 6 ohm resistors considered to be in parallel?

They have the same voltage across them

They are connected to the same node

They are physically adjacent

They have the same current flowing through them

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the potential difference across the 4 ohm resistor?

VD - VC

VC - VB

VA - VB

VD - VB

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equivalent resistance of two resistors in parallel with resistances of 3 ohms and 6 ohms?

1 ohm

2 ohms

3 ohms

4 ohms

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which resistors are in parallel in the final network simplification?

3 ohm and 6 ohm

1 ohm and 5 ohm

4 ohm and 12 ohm

2 ohm and 10 ohm

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the equivalent resistance calculated for two resistors in parallel?

Subtract the smaller resistance from the larger

Add their resistances

Multiply their resistances and divide by their sum

Divide the larger resistance by the smaller

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