Forces and Equilibrium in Meter Sticks

Forces and Equilibrium in Meter Sticks

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains how to solve a physics problem involving a uniform meter stick supported at two points with an object placed on it. The tutorial covers drawing a free body diagram, identifying forces, and understanding translational and rotational equilibrium. It demonstrates calculating net torque and solving for normal forces using equations. The tutorial concludes with verifying the results using force sensors, confirming the physics principles discussed.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the mass of the meter stick used in the problem?

0.250 kg

0.200 kg

0.093 kg

0.150 kg

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where is the object placed on the meter stick?

50 cm mark

92 cm mark

6 cm mark

15 cm mark

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of drawing a Freebody diagram in this context?

To calculate the mass of the object

To visualize the forces acting on the meter stick

To find the center of mass

To determine the length of the meter stick

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does it mean for the meter stick to be in translational equilibrium?

The net torque acting on it is zero

The net force acting on it is zero

It is moving at a constant speed

It is rotating with constant angular velocity

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the context of this problem, what does static equilibrium imply?

The forces are unbalanced

The meter stick is rotating

The net force and net torque are both zero

The object is accelerating

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the net torque calculated in this problem?

By dividing the forces by distance

By summing the torques about a chosen axis

By multiplying the mass by acceleration

By adding all the forces

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the calculated value of the normal force at the 92 cm mark?

1.5 N

0.25 N

3.2 N

0.13 N

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