Ionic Compounds and Their Properties

Ionic Compounds and Their Properties

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to write the chemical formula for tin(IV) fluoride. It begins by identifying the element symbols for tin and fluorine on the periodic table. Tin, being a transition metal, has a four-plus ionic charge, while fluorine, a non-metal, has a one-minus ionic charge. The tutorial demonstrates how to balance these charges to achieve a net charge of zero, resulting in the formula SnF4. The video concludes with a brief summary of the process.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the element symbol for tin, and what is its ionic charge?

Sn, with a four-plus charge

Ti, with a two-plus charge

Sn, with a two-plus charge

Ti, with a four-plus charge

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the compound formed between tin and fluorine considered ionic?

Because both are metals

Because they have the same charge

Because tin is a metal and fluorine is a non-metal

Because both are non-metals

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the ionic charge of a fluorine atom?

Two-plus

One-plus

Two-minus

One-minus

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many fluorine atoms are needed to balance the charge of one tin atom in tin(IV) fluoride?

Two

Three

Four

Five

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the chemical formula for tin(IV) fluoride?

SnF2

SnF3

SnF4

SnF5