Net Ionic Equations and Reactions

Net Ionic Equations and Reactions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Liam Anderson

FREE Resource

This video tutorial guides viewers through writing a balanced net ionic equation for the reaction between sulfuric acid (H2SO4) and barium bromide (BaBr2). It begins with balancing the molecular equation, assigning states to substances based on solubility rules, and then splitting strong electrolytes into ions for the complete ionic equation. The tutorial explains how to identify and remove spectator ions to form the net ionic equation, ensuring charge and atom balance. The video concludes with a verification of the final net ionic equation.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing a net ionic equation?

Split compounds into ions

Determine the states of substances

Balance the molecular equation

Identify spectator ions

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you balance the number of hydrogen atoms in the reaction between H2SO4 and BaBr2?

Add a coefficient of 2 in front of BaSO4

Add a coefficient of 2 in front of BaBr2

Add a coefficient of 2 in front of HBr

Add a coefficient of 2 in front of H2SO4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a strong acid that dissociates completely in water?

Barium sulfate

Sodium chloride

Sulfuric acid

Barium bromide

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the state of barium sulfate in the reaction?

Aqueous

Gas

Liquid

Solid

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge of the sulfate ion in the complete ionic equation?

2-

1-

1+

2+

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which ions are considered spectator ions in the reaction?

Hydrogen and barium ions

Bromide and sulfate ions

Hydrogen and bromide ions

Barium and sulfate ions

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the net charge on both sides of the net ionic equation?

2+

0

2-

1+

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