Net Ionic Equations and Reactions

The video tutorial explains how to write a balanced net ionic equation for the reaction between silver nitrate and hydrogen sulfide. It begins by introducing the problem and then demonstrates how to balance the molecular equation. The tutorial covers assigning states to each substance, considering solubility rules, and writing the complete ionic equation. Finally, it shows how to derive the net ionic equation by removing spectator ions, ensuring charge and mass balance. The video concludes with a summary of the balanced net ionic equation.

What is the main focus of this video tutorial?

• Balancing chemical equations

• Understanding molecular geometry

• Learning about gas laws

• Writing net ionic equations

What is the first step in balancing the molecular equation for the reaction?

• Balancing the oxygen atoms

• Balancing the nitrogen atoms

• Balancing the silver atoms

• Balancing the hydrogen atoms

What is the state of silver nitrate in the reaction?

• Solid

• Liquid

• Gas

• Aqueous

Which substance forms a precipitate in the reaction?

• Silver sulfide

• Hydrogen sulfide

• Nitric acid

• Silver nitrate

Why is hydrogen sulfide not split into ions in the net ionic equation?

• It is a strong base

• It is a weak acid

• It is a weak base

• It is a strong acid

What is the charge of the silver ion in the complete ionic equation?

• 2+

• 1+

• 1-

• 2-

What is the role of nitric acid in the reaction?

• It acts as a weak acid

• It forms a precipitate

• It is a strong electrolyte

• It is a weak electrolyte

What type of ions are removed to derive the net ionic equation?

• Neutral ions

• Spectator ions

• Product ions

• Reactant ions

What is the significance of balancing charges in the net ionic equation?

• To ensure mass conservation

• To ensure charge conservation

• To identify spectator ions

• To determine solubility

What happens to the nitrate ions in the net ionic equation?

• They form a solid

• They are split into ions

• They react with silver

• They remain as spectator ions