Valence Electrons and Lewis Structures

Valence Electrons and Lewis Structures

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Amelia Wright

FREE Resource

The video tutorial explains how to write the Lewis structure for tin tetrachloride (SnCl4). It begins by introducing the compound and its alternative name, tin four chloride. The tutorial then guides viewers through counting the valence electrons, placing the tin atom in the center, and arranging the chlorine atoms around it. The process of forming chemical bonds and completing the octets for each atom is detailed, resulting in the final Lewis structure for SnCl4.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons in SnCl4?

28

32

36

40

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the tin atom placed at the center of the SnCl4 structure?

It is the most electronegative atom.

It has the smallest atomic radius.

It has the highest atomic number.

It is the least electronegative atom.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to form bonds between tin and chlorine atoms in SnCl4?

4

8

16

12

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of completing the octets for chlorine atoms in SnCl4?

To change the molecular shape

To reduce the number of valence electrons

To ensure chemical stability

To increase the molecular weight

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many total valence electrons are used in the final Lewis structure of SnCl4?

32

24

28

36

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is achieved when both tin and chlorine atoms have octets in SnCl4?

Increased reactivity

Chemical instability

A change in molecular formula

A complete Lewis structure