Lewis Structures and Valence Electrons

Lewis Structures and Valence Electrons

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Sophia Harris

FREE Resource

This video tutorial explains how to write the Lewis structure for the SF5+ ion. It begins by counting the valence electrons, considering the positive charge, and calculating a total of 40 valence electrons. The sulfur atom is placed at the center due to its lower electronegativity compared to fluorine. Five fluorine atoms are arranged around sulfur, and electrons are distributed to form bonds and complete octets. The video highlights that sulfur can have an expanded octet, accommodating more than eight electrons. The final structure is presented with brackets and a positive sign to indicate the ion's charge.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in writing the Lewis structure for the SF5+ ion?

Draw the skeletal structure

Identify the central atom

Count the valence electrons

Determine the molecular geometry

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does sulfur contribute in the SF5+ ion?

10

4

8

6

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the positive charge in SF5+ indicate?

A neutron has been removed

An extra electron is present

A proton has been added

An electron has been lost

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many total valence electrons are there in the SF5+ ion?

42

44

40

38

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the SF5+ Lewis structure?

Nitrogen

Oxygen

Fluorine

Sulfur

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is sulfur chosen as the central atom in the SF5+ ion?

It has the smallest atomic radius

It is the most electronegative

It has the highest atomic number

It is the least electronegative

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of distributing electrons around the atoms in a Lewis structure?

To calculate the molecular weight

To complete the octets

To determine the molecular shape

To balance the equation

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