Iodine and Fluorine in IF7

The video tutorial explains how to find the oxidation number of iodine in iodine heptafluoride (IF7). It begins by noting that IF7 is a neutral compound, meaning the sum of its oxidation numbers is zero. Fluorine, being more electronegative, has an oxidation number of -1. With seven fluorine atoms, the total is -7. Therefore, iodine must have an oxidation number of +7 to balance the compound to zero. The video concludes by summarizing these calculations.

What is the overall charge of the compound IF7?

• Depends on the temperature

• Neutral

• Negative

• Positive

How many fluorine atoms are present in IF7?

• 7

• 8

• 6

• 5

What is the oxidation number assigned to each fluorine atom in IF7?

• -1

• +1

• +7

• 0

To balance the oxidation numbers in IF7, what must be the oxidation number of iodine?

• +5

• +6

• +7

• +8

Why does iodine in IF7 have an oxidation number of +7?

• To balance the -7 from fluorine

• Because iodine is more electronegative

• Due to its atomic number

• It is a random assignment