Solubility and Ionic Reactions

The video tutorial explains how to write a balanced net ionic equation for the reaction between ammonium bromide (NH4Br) and silver nitrate (AgNO3). It begins with balancing the molecular equation, followed by determining the states of each compound using solubility rules. The tutorial then breaks down the compounds into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation. The video concludes by ensuring charge conservation and balancing of atoms in the final equation.

What is the first step in writing a net ionic equation?

• Balance the molecular equation

• Identify spectator ions

• Determine the solubility of compounds

• Write the complete ionic equation

Which of the following compounds is generally insoluble in water?

• Potassium nitrate

• Sodium chloride

• Silver bromide

• Ammonium nitrate

What does the 'aq' state symbol indicate about a compound?

• It is a solid

• It is a liquid

• It is soluble in water

• It is insoluble in water

What is the charge of the ammonium ion?

• 1+

• 1-

• 2+

• 2-

Which ion is always present in a nitrate compound?

• Br-

• NO3-

• Ag+

• NH4+

What is the purpose of identifying spectator ions in a reaction?

• To determine solubility

• To simplify the net ionic equation

• To identify reactants

• To balance the equation

Which ions are considered spectator ions in the reaction between NH4Br and AgNO3?

• NH4+ and NO3-

• NO3- and Br-

• Ag+ and Br-

• NH4+ and Ag+

What is the net charge of the final net ionic equation?

• 2+

• 1-

• 1+

• 0

Why is it important to ensure that the atoms are balanced in the net ionic equation?

• To simplify the equation

• To determine solubility

• To identify spectator ions

• To conserve mass

What is the final product formed in the reaction between NH4Br and AgNO3?

• Silver bromide

• Ammonium bromide

• Silver nitrate

• Ammonium nitrate