Atoms and Molecules in NaNO3

Atoms and Molecules in NaNO3

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial explains how to determine the number of atoms in sodium nitrate (NaNO3). It begins by identifying the elements in NaNO3: sodium (Na), nitrogen (N), and oxygen (O). The tutorial then demonstrates how to count the total number of atoms in NaNO3, which is five. It further explains how to calculate the number of oxygen atoms in one mole of NaNO3 using Avogadro's number, resulting in 18.06 x 10^23 atoms. Similarly, it shows how to find the number of sodium atoms in one mole, which is 6.02 x 10^23 atoms. The video concludes with a brief sign-off by Dr. B.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the elements present in the chemical formula NaNO3?

Sodium, Nitrogen, Oxygen

Sodium, Nitrogen, Hydrogen

Sodium, Oxygen, Carbon

Nitrogen, Oxygen, Carbon

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many atoms of sodium are present in a single molecule of NaNO3?

One

Three

Four

Two

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the subscript '3' in NaNO3?

It indicates the number of molecules

It indicates the number of sodium atoms

It indicates the number of nitrogen atoms

It indicates the number of oxygen atoms

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of atoms in a molecule of NaNO3?

Seven

Five

Six

Four

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many atoms of oxygen are there in one mole of NaNO3?

9.03 x 10^23

6.02 x 10^23

3.01 x 10^23

18.06 x 10^23

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is Avogadro's number used for in chemistry?

To measure the volume of a gas

To find the mass of an element

To determine the number of atoms in a mole

To calculate the number of molecules in a compound

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many sodium atoms are present in one mole of NaNO3?

18.06 x 10^23

6.02 x 10^23

24.08 x 10^23

12.04 x 10^23