Net Ionic Equations and Spectator Ions

This video tutorial explains how to write the net ionic equation for the reaction between aluminum and copper(II) sulfate. It begins with balancing the molecular equation and identifying the states of each substance using solubility rules. The tutorial then demonstrates how to split soluble compounds into their respective ions to form the complete ionic equation. Finally, it shows how to identify and cross out spectator ions to derive the net ionic equation.

What is the first step in writing a net ionic equation?

• Determine the solubility of compounds

• Write the balanced molecular equation

• Identify spectator ions

• Split compounds into ions

What are the coefficients for the balanced molecular equation of Al and CuSO4?

• 1, 1, 1, 1

• 2, 3, 1, 3

• 3, 2, 1, 2

• 2, 1, 3, 1

How do you determine the state of copper sulfate in the reaction?

• By measuring its temperature

• By observing its reaction with water

• By using a solubility table

• By checking its color

What does 'aq' stand for when writing chemical equations?

• Aqueous

• Aqueous liquid

• Aqueous solid

• Aqueous gas

What is the charge on the aluminum ion in the reaction?

• 4+

• 1+

• 2+

• 3+

Which ion is not split into its components in the complete ionic equation?

• Aluminum

• Copper

• Sulfate

• Water

What are spectator ions?

• Ions that are only in the reactants

• Ions that are only in the products

• Ions that do not change during the reaction

• Ions that participate in the reaction

Which ions are removed to form the net ionic equation?

• Spectator ions

• Product ions

• Only reactant ions

• All ions

What is the final step in writing the net ionic equation?

• Determining the states of substances

• Cleaning up the equation

• Identifying spectator ions

• Balancing the equation

What is the purpose of writing a net ionic equation?

• To show all compounds involved

• To balance the chemical equation

• To determine the solubility of compounds

• To highlight the ions that participate in the reaction