Balancing Iron(II) Sulfate Reactions

The video tutorial explains the decomposition of iron(II) sulfate into iron(III) oxide, sulfur dioxide, and sulfur trioxide. It demonstrates how to balance the chemical equation by counting the atoms on each side and adjusting coefficients to ensure the same number of each type of atom appears on both sides of the equation. The tutorial concludes with the balanced equation for the decomposition reaction.

What are the products formed when iron(II) sulfate decomposes?

• FeO, SO3, and O2

• FeO, SO2, and SO3

• Fe2O3, SO2, and SO3

• Fe2O3, SO3, and O2

How many sulfur atoms are present on the product side before balancing?

• One

• Two

• Four

• Three

What is the total number of oxygen atoms on the product side before balancing?

• Seven

• Eight

• Six

• Five

What coefficient is used in front of FeSO4 to balance the equation?

• 1

• 2

• 3

• 4

After balancing, how many iron atoms are present on each side of the equation?

• Four

• Three

• Two

• One

What is the balanced equation for the decomposition of FeSO4?

• FeSO4 → Fe2O3 + SO2 + SO3

• 2FeSO4 → Fe2O3 + SO2 + SO3

• FeSO4 → 2Fe2O3 + SO2 + SO3

• 2FeSO4 → Fe2O3 + 2SO2 + SO3