Silver Iodide and Transition Metals

Silver Iodide and Transition Metals

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to write the formula for silver iodide by identifying silver and iodine on the periodic table. It discusses the nature of ionic compounds, focusing on the charges of silver and iodine. Silver, a transition metal, has a consistent charge of +1, while iodine has a charge of -1. The tutorial emphasizes the importance of balancing these charges to achieve a neutral compound, resulting in the formula AgI. The video concludes with a clean-up of the formula and a brief thank you from Dr. B.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which elements are involved in the formation of silver iodide?

Silver and Chlorine

Silver and Iodine

Gold and Iodine

Gold and Chlorine

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of compound is formed when a metal and a non-metal combine?

Covalent compound

Ionic compound

Metallic compound

Molecular compound

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge on a silver ion in silver iodide?

2-

1-

1+

2+

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the charge on an iodine ion in silver iodide?

1-

1+

2+

2-

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is silver considered an exception among transition metals?

It is not a metal

It has a variable charge

It always has a 1+ charge

It forms covalent bonds

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final formula for silver iodide?

AgI2

Ag2I2

Ag2I

AgI