Calcium and Hydrochloric Acid Reactions

The video tutorial explains how to write a net ionic equation for the reaction between calcium and hydrochloric acid. It covers the steps of balancing the molecular equation, identifying the states of substances, splitting soluble compounds into ions, and writing the complete ionic equation. Finally, it demonstrates how to identify and cross out spectator ions to arrive at the net ionic equation.

What type of reaction is the interaction between calcium and hydrochloric acid?

• Single displacement reaction

• Decomposition reaction

• Double displacement reaction

• Synthesis reaction

What is the balanced molecular equation for the reaction between calcium and hydrochloric acid?

• Ca + 2HCl → Ca + H2

• Ca + 2HCl → CaCl2 + H2

• Ca + HCl → CaCl2 + H2

• Ca + HCl → Ca + H2

What is the state of calcium in the reaction with hydrochloric acid?

• Solid

• Gas

• Aqueous

• Liquid

Which ion has a 1+ charge in the reaction between calcium and hydrochloric acid?

• Oxygen ion

• Hydrogen ion

• Calcium ion

• Chloride ion

What is the charge of the calcium ion in the reaction?

• 2-

• 1+

• 2+

• 1-

Why is hydrogen gas not split into ions in the reaction?

• It is a solid

• It is a gas and not soluble

• It is a liquid

• It is an aqueous solution

What is the complete ionic equation for the reaction between calcium and hydrochloric acid?

• Ca + H+ + Cl- → Ca2+ + Cl- + H2

• Ca + 2H+ + Cl- → Ca2+ + Cl- + H2

• Ca + 2H+ + 2Cl- → Ca2+ + 2Cl- + H2

• Ca + H+ + 2Cl- → Ca2+ + 2Cl- + H2

Which ions are considered spectator ions in the reaction?

• Calcium ions

• Hydrogen ions

• Chloride ions

• Oxygen ions

What is the net ionic equation for the reaction between calcium and hydrochloric acid?

• Ca + H+ → Ca2+ + H2

• Ca + 2H+ + Cl- → Ca2+ + Cl- + H2

• Ca + 2H+ → Ca2+ + H2

• Ca + 2H+ + 2Cl- → Ca2+ + 2Cl- + H2

What happens to the chloride ions in the net ionic equation?

• They are included in the equation

• They change their charge

• They are removed as spectator ions

• They form a new compound