Valence Electrons in IBr Molecule

The video tutorial explains how to draw the Lewis structure for iodine bromide (IBr). It begins by counting the valence electrons of iodine and bromine, both of which belong to group 17 and have seven valence electrons each, totaling 14. The tutorial then demonstrates how to draw iodine and bromine, placing two electrons between them to form a chemical bond. The video continues by ensuring each atom achieves an octet, using all 14 valence electrons. Finally, the completed Lewis structure for IBr is presented, with both iodine and bromine having eight valence electrons.

How many valence electrons does iodine contribute to the IBr molecule?

• 5

• 6

• 7

• 8

What is the total number of valence electrons in the IBr molecule?

• 18

• 12

• 16

• 14

What is the first step in forming the Lewis structure for IBr?

• Completing the octet for iodine

• Drawing iodine and bromine next to each other

• Counting the total number of electrons

• Placing iodine and bromine far apart

How many electrons are shared between iodine and bromine to form a bond?

• 1

• 2

• 4

• 3

What ensures that both iodine and bromine have a complete octet in the IBr Lewis structure?

• Adding more electrons to iodine

• Removing electrons from bromine

• Sharing electrons with another atom

• Ensuring each atom has eight valence electrons