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Balancing Chemical Equations with Polyatomic Ions

Balancing Chemical Equations with Polyatomic Ions

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Practice Problem

Easy

Created by

Aiden Montgomery

Used 4+ times

FREE Resource

The video tutorial explains how to balance the chemical equation of copper(II) sulfate reacting with sodium hydroxide to form copper(II) hydroxide and sodium sulfate. It begins by counting the atoms on both the reactant and product sides, highlighting the importance of recognizing polyatomic ions like sulfate (SO4) and hydroxide (OH) as single units. The tutorial then demonstrates balancing the equation by adjusting coefficients, particularly focusing on sodium and hydroxide ions. The key takeaway is the simplification of balancing by treating polyatomic ions as single entities when they appear unchanged on both sides of the equation.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial chemical equation that needs to be balanced?

CuSO4 + NaOH → Cu(OH)2 + Na2SO4

CuSO4 + NaOH → Cu(OH)2 + 2Na2SO4

2CuSO4 + NaOH → Cu(OH)2 + Na2SO4

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many copper atoms are present on the reactant side of the equation?

Two

Four

One

Three

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of recognizing polyatomic ions like SO4 in balancing equations?

They can be ignored completely.

They should be counted separately as individual atoms.

They should be split into individual elements.

They can be counted as a single unit if they appear on both sides.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What coefficient is added in front of NaOH to balance the sodium atoms?

3

4

2

1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After balancing, how many hydroxide ions (OH) are present on the product side?

One

Two

Three

Four

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final balanced equation for the reaction?

CuSO4 + NaOH → Cu(OH)2 + Na2SO4

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

2CuSO4 + NaOH → Cu(OH)2 + 2Na2SO4

CuSO4 + NaOH → 2Cu(OH)2 + Na2SO4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it easier to balance equations when polyatomic ions are treated as single units?

It simplifies the counting of atoms.

It reduces the number of calculations needed.

It increases the complexity of the equation.

It allows for more flexibility in balancing.

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