IF4+ Lewis Structure Concepts

IF4+ Lewis Structure Concepts

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Practice Problem

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to draw the Lewis structure for IF4+. It begins by counting the valence electrons, considering iodine and fluorine's group numbers, and accounting for the positive charge. Iodine is placed at the center due to its lower electronegativity, surrounded by four fluorine atoms. The tutorial ensures all atoms have complete octets, using 32 of the 34 available electrons. The remaining electrons are placed on iodine, which can have an expanded octet. The structure is finalized by adding brackets and a plus sign to indicate the ion's positive charge.

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many total valence electrons are there in the IF4+ Lewis structure?

32

38

34

36

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the IF4+ Lewis structure?

Carbon

Fluorine

Iodine

Oxygen

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many fluorine atoms are bonded to iodine in the IF4+ structure?

5

4

3

2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are used to form bonds between iodine and fluorine atoms?

12

10

8

6

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons used in forming bonds in the IF4+ structure?

16

24

40

32

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the octet rule concerning fluorine atoms in the IF4+ structure?

Fluorine does not follow the octet rule

Fluorine can have less than 8 valence electrons

Fluorine must have exactly 8 valence electrons

Fluorine can have more than 8 valence electrons

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can iodine have more than 8 valence electrons in the IF4+ structure?

Iodine is a noble gas

Iodine can have an expanded octet

Iodine can form double bonds

Iodine is highly electronegative

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