Valence Electrons in N2F2 Molecule

Valence Electrons in N2F2 Molecule

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains the process of drawing the Lewis structure for N2F2. It begins by calculating the total valence electrons, positioning the atoms based on electronegativity, and forming initial bonds. The tutorial then demonstrates how to use all valence electrons to complete the octets, including shifting electrons to form a double bond for full octet completion. Finally, it checks the formal charges to ensure they are zero, confirming the correct Lewis structure.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does nitrogen contribute in the N2F2 molecule?

10

5

14

7

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons available for the N2F2 molecule?

30

28

24

20

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Where are the nitrogen atoms placed in the N2F2 Lewis structure?

On the outside

At the center

Between the fluorines

At the corners

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What adjustment is made to ensure all atoms have full octets in the N2F2 molecule?

Changing atom positions

Forming a double bond

Removing electrons

Adding more electrons

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does each nitrogen atom have after forming a double bond?

9

8

7

6

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on each atom in the final N2F2 Lewis structure?

+1

-1

+2

0

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of having zero formal charge on all atoms in a Lewis structure?

It confirms the structure is stable

It shows the structure is incorrect

It means more electrons are needed

It indicates instability