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Chlorate Ion Lewis Structure Concepts

Chlorate Ion Lewis Structure Concepts

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Practice Problem

Hard

Created by

Liam Anderson

FREE Resource

The video tutorial explains how to draw the Lewis structure for ClO4-. It begins by calculating the total valence electrons, placing Chlorine in the center, and arranging the Oxygens around it. Bonds are formed, and formal charges are calculated. Adjustments are made by creating double bonds to minimize formal charges, resulting in a stable structure. The final structure is enclosed in brackets to indicate it is a negative ion.

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9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does Chlorine contribute to the ClO4- structure?

8

5

6

7

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons used in the ClO4- Lewis structure?

28

30

32

34

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is Chlorine placed at the center of the ClO4- structure?

It has the highest atomic number

It is the most electronegative

It is the least electronegative

It has the smallest atomic radius

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on Chlorine before adjusting the structure?

+3

0

+1

+2

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the goal when adjusting formal charges in a Lewis structure?

To maximize the number of bonds

To make all charges positive

To increase the number of lone pairs

To make formal charges as close to zero as possible

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How are the formal charges resolved in the ClO4- structure?

By removing Chlorine

By creating double bonds

By adding more electrons

By adding more Oxygen atoms

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formal charge on each Oxygen atom after creating double bonds?

+1

-2

0

-1

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