Why might integration not always be feasible for finding the area under a curve?

Trapezium Area and Construction Concepts

Interactive Video
•
Mathematics
•
9th - 10th Grade
•
Hard

Ethan Morris
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Integration is too simple for complex functions.
Some functions are too complex or undefined for integration.
Integration always gives an approximate result.
Integration is only applicable to linear functions.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in constructing a trapezium to approximate an area under a curve?
Calculate the exact area using integration.
Identify the curve's maximum point.
Draw a rectangle under the curve.
Connect the top points above the x-axis with a straight line.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the 'h' represent in the trapezium area formula?
The perpendicular height between the parallel sides.
The average of the parallel sides.
The total area of the trapezium.
The horizontal length of the trapezium.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it important to identify the parallel sides in a trapezium?
They determine the height of the trapezium.
They are always the longest sides.
They are used to find the midpoint of the trapezium.
They are used to calculate the area of the trapezium.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why are 'a' and 'b' replaced with 'y1' and 'y2' in the context of integral calculus?
To avoid confusion with boundaries.
To make the formula more complex.
To simplify the calculation process.
Because 'a' and 'b' are not applicable in calculus.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you determine the value of 'h' in the trapezium formula?
By dividing the area by the sum of the parallel sides.
By measuring the vertical distance between the parallel sides.
By subtracting the lower boundary from the upper boundary on the x-axis.
By adding the lengths of the parallel sides.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of substituting x = 3 into the function y = x^2?
12
3
9
6
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