Light Intensity Reduction and Inequalities

Light Intensity Reduction and Inequalities

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains a problem related to geometric progressions, specifically focusing on how light intensity is reduced when passing through multiple sheets of glass. The problem is set up by establishing a geometric series model, and two methods are presented to solve it: using inequalities and equations. Each method is explained in detail, highlighting the pros and cons, and the importance of understanding logarithms in solving such problems.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main topic of the problem discussed in the video?

Arithmetic Progressions

Geometric Progressions

Linear Equations

Quadratic Equations

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How much does the intensity of light reduce when passing through one sheet of glass?

7%

3%

10%

5%

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the intensity of light that passes through a single sheet of glass expressed as a decimal?

0.97

0.93

0.95

0.99

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What mathematical concept is used to solve the inequality for the number of sheets?

Matrix Multiplication

Logarithms

Differentiation

Integration

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to consider the direction of the inequality when dividing by a negative number?

It changes the solution to a quadratic equation.

It converts the inequality to an equation.

It affects the sign of the inequality.

It has no effect on the inequality.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the minimum number of sheets required to reduce the light intensity below 1%?

150

151

153

152

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the alternative method to solve the problem instead of using inequalities?

Using integration

Using equations

Using matrices

Using differentiation

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