Bisection Method and Polynomial Analysis

Bisection Method and Polynomial Analysis

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explores a polynomial problem involving a cubic equation with one root between 0 and 1. Initially, the discriminant and calculus are considered but found unhelpful. The focus shifts to polynomial methods, particularly the bisection method, which relies on sign changes to find roots. The tutorial demonstrates how to apply this method to prove that 2 - k is negative, emphasizing the importance of understanding the problem's constraints and using appropriate mathematical techniques.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main challenge in solving the polynomial x^3 - kx + 1 = 0?

Finding the discriminant

Solving a quadratic equation

Identifying the correct method

Calculating the derivative

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is the discriminant not useful for solving the given cubic polynomial?

It provides multiple roots

It is too complex to calculate

It is not applicable to cubic equations

It only applies to linear equations

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does differentiating the polynomial x^3 - kx + 1 yield?

2x - k

3x^2 - k

3x - k

x^2 - k

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which method is used to approximate roots by halving the interval?

Quadratic formula

Discriminant method

Bisection method

Newton's method

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the key feature of the bisection method?

It uses derivatives

It finds exact roots

It relies on sign changes

It requires the discriminant

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the bisection method, what indicates the presence of a root?

A positive discriminant

A zero derivative

A change in sign

A constant function value

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of P(0) for the polynomial x^3 - kx + 1?

k

0

-1

1

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