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Factoring and Solving Quadratic Expressions

Factoring and Solving Quadratic Expressions

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to find the zeros of quadratic expressions. It covers two examples: the first uses the difference of squares method to factor x^2 - 25, resulting in zeros at x = 5 and x = -5. The second example involves recognizing a perfect square trinomial in 4d^2 - 36d + 81, which factors to (2D - 9)^2, yielding a single zero at D = 9/2.

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9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the zeros of a quadratic expression?

Factor the expression

Set the expression equal to zero

Use the quadratic formula

Complete the square

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What pattern is recognized in the expression x^2 - 25?

Perfect square trinomial

Sum of cubes

Difference of squares

Quadratic formula

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the expression x^2 - 25 factored?

(x - 5)(x + 5)

(x + 5)(x - 5)

(x - 5)(x - 5)

(x + 5)(x + 5)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the zeros of the expression x^2 - 25?

0 and 5

5 and -5

-5 and 0

5 and 5

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What type of expression is 4d^2 - 36d + 81?

Difference of squares

Linear expression

Perfect square trinomial

Sum of cubes

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'a' in the expression 4d^2 - 36d + 81?

4d

2d

36d

9

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'b' in the expression 4d^2 - 36d + 81?

2d

4d

36d

9

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