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Finding X Intercepts of Quadratic Equations

Finding X Intercepts of Quadratic Equations

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Easy

Created by

Emma Peterson

Used 1+ times

FREE Resource

The video tutorial explains how to determine the X intercepts or zeros of a quadratic equation. It introduces the concept of X intercepts on a graph and explains the intercept form of a quadratic equation, which is expressed as a * (x - p) * (x - Q). The tutorial then demonstrates how to identify the X intercepts by analyzing the equation y = (x - 3) * (x + 5), resulting in X intercepts at X = 3 and X = -5.

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9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of X intercepts in a graph?

They indicate where the graph crosses the Y-axis.

They show the maximum points of the graph.

They represent where the graph touches the X-axis.

They are the points where the graph is undefined.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the intercept form of a quadratic equation, what do the variables p and q represent?

The roots of the equation.

The Y intercepts of the equation.

The X intercepts of the equation.

The coefficients of the quadratic terms.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the intercept form of a quadratic equation?

y = a(x - p)(x - q)

y = a(x + p)(x + q)

y = ax^2 + bx + c

y = ax^2 + c

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation y = (x - 3)(x + 5), what is the value of 'a'?

0

1

5

3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the first X intercept from the equation y = (x - 3)(x + 5)?

By setting y = 0

By setting x = 0

By setting x - 3 = 0

By setting x + 5 = 0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first X intercept of the equation y = (x - 3)(x + 5)?

x = -5

x = -3

x = 3

x = 5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you find the second X intercept in the equation y = (x - 3)(x + 5)?

By setting x - 3 = 0

By setting y = 0

By setting x + 5 = 0

By setting x = 0

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