Valence Electrons in XeF3- Structure

The video tutorial explains how to draw the Lewis structure for XeF3-. It begins by calculating the total number of valence electrons, placing xenon in the center, and arranging fluorine atoms around it. The tutorial ensures that fluorine atoms have complete octets and discusses the concept of an extended octet for xenon. Finally, it reviews the complete Lewis structure, highlighting the correct distribution of electrons.

How many valence electrons are there in total for XeF3-?

• 28

• 34

• 30

• 32

Which atom is placed at the center of the XeF3- structure?

• Oxygen

• Xenon

• Hydrogen

• Fluorine

How many electrons are used to form bonds between xenon and fluorine atoms?

• 10

• 6

• 4

• 8

What is the total number of valence electrons used to complete the octets for the fluorine atoms?

• 20

• 18

• 24

• 22

Why can't the remaining valence electrons be placed on the fluorine atoms?

• Fluorine atoms are too small

• Fluorine atoms are in period two and can only hold eight valence electrons

• Fluorine atoms are already bonded

• Fluorine atoms are too electronegative

What allows xenon to hold more than eight valence electrons?

• It forms ionic bonds

• It can have an extended octet

• It is in period two

• It is highly electronegative

How many valence electrons does xenon have in the final structure of XeF3-?

• 8

• 10

• 12

• 6

What is the significance of the negative charge in the Lewis structure of XeF3-?

• It adds an extra valence electron

• It indicates a missing electron

• It reduces the number of bonds

• It changes the central atom