Finding Inverse Functions with Logarithms

Finding Inverse Functions with Logarithms

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to find the inverse of the function 3^(x-1) + 2. It involves replacing f(x) with y, switching x and y, solving for y, and using logarithms to simplify the equation. The final inverse function is expressed in terms of log base 3. The tutorial provides a step-by-step approach to understanding and solving the problem.

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial function we are trying to find the inverse of?

x to the 3 minus 1 plus 2

3 to the x minus 1 plus 2

3 to the x plus 1 minus 2

3 to the x minus 2 plus 1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in finding the inverse of a function?

Switch x and y

Replace f(x) with y

Add 2 to both sides

Take the log of both sides

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of replacing f(x) with y in the process?

To prepare for switching x and y

To solve for x

To simplify the equation

To take the logarithm

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After replacing f(x) with y, what is the next step?

Switch x and y

Add 1 to both sides

Subtract 2 from both sides

Take the log base 3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why do we switch x and y in the process of finding an inverse?

To express the inverse function

To change the base of the logarithm

To solve for y

To isolate the term

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is performed to isolate the term 3 to the y minus 1?

Add 2 to both sides

Multiply both sides by 3

Subtract 2 from both sides

Divide both sides by 3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of subtracting 2 from both sides?

To express the inverse function

To solve for x

To isolate the exponential term

To change the base of the logarithm

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