Triangle Area and Trigonometry Concepts

Triangle Area and Trigonometry Concepts

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to find the area of a triangle using trigonometry. It starts with the basic formula for area using base and height, then introduces a scenario where the height is unknown but another side and an angle are given. By using the sine function, the height can be calculated, allowing the area to be determined. A general formula is derived for any triangle, and example problems are provided to reinforce the concept.

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the basic formula for finding the area of a triangle when the base and height are known?

1/2 * base * height

base * height

base + height

1/3 * base * height

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example given, what is the area of a triangle with a base of 18 and a height of 10?

80 square units

90 square units

110 square units

100 square units

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to ensure the height involves a right angle in the basic area formula?

To simplify calculations

To ensure the formula is applicable

To make the triangle equilateral

To avoid using trigonometry

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What additional information is given in the scenario where the height is unknown?

The perimeter of the triangle

The area of the triangle

The type of triangle

Another side and an angle

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the scenario with unknown height, what is the angle given?

60°

30°

37°

45°

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What trigonometric function is used to find the height of the triangle?

Cosine

Tangent

Secant

Sine

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the height of the triangle represented in terms of the given angle and side?

H = 12 / sin(37°)

H = 12 * cos(37°)

H = 12 * sin(37°)

H = 12 * tan(37°)

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