Calculating Areas Under Curves

Calculating Areas Under Curves

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

This video tutorial teaches how to find the area under a curve using integration. It begins with an introduction to the concept and explains the generic case of calculating the area using definite integrals. The video then provides three examples, each increasing in complexity. The first example covers a simple integration of y=x^2, the second deals with a symmetrical curve y=x^3, and the third involves finding the area between a curve and a straight line. The tutorial concludes with additional resources for further learning.

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44 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary mathematical concept used to find the area under a curve?

Algebra

Integration

Trigonometry

Differentiation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What must you know to calculate a definite integral?

How to integrate

How to graph functions

How to solve equations

How to differentiate

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of the video tutorial?

To teach differentiation

To teach trigonometry

To teach integration

To teach algebra

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the prerequisite knowledge for understanding the video tutorial?

Trigonometry

Algebra

Integration

Differentiation

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main focus of the video tutorial?

Finding the area under a curve

Solving equations

Calculating derivatives

Graphing functions

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the generic case, what do you calculate to find the area under a curve between two points?

The average value of the function

The definite integral of the function

The derivative of the function

The slope of the tangent line

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula used to find the area under a curve between x = a and x = b?

f'(b) - f'(a)

∫[a, b] f(x) dx

f(b) - f(a)

∫[a, b] f'(x) dx

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