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Understanding Functions and Discontinuities

Understanding Functions and Discontinuities

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to analyze a rational function by factoring it to identify removable and non-removable discontinuities. It also covers how to find vertical and horizontal asymptotes, and determine the domain and range of the function. The instructor emphasizes the importance of factoring and provides a step-by-step approach to solving the problem.

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the function given in the problem?

x^2 - 2x - 8 / x^2 - 5x - 4

x^2 - 2x + 8 / x^2 - 5x + 4

x^2 + 2x - 8 / x^2 + 5x + 4

x^2 + 2x + 8 / x^2 + 5x - 4

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is factoring important in solving this problem?

It simplifies the function for easier analysis.

It changes the function to a polynomial.

It eliminates the need for asymptotes.

It makes the function continuous.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a removable discontinuity?

A point where the function is undefined but can be canceled out.

A point where the function is undefined and cannot be canceled out.

A point where the function has a vertical asymptote.

A point where the function is continuous.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which value of x represents a removable discontinuity in this problem?

x = 1

x = -4

x = 0

x = -1

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a non-removable discontinuity?

A point where the function has a horizontal asymptote.

A point where the function is continuous.

A point where the function is undefined and cannot be canceled out.

A point where the function is undefined but can be canceled out.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which value of x represents a non-removable discontinuity in this problem?

x = 1

x = 0

x = -1

x = -4

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the function at a removable discontinuity?

The function has a vertical asymptote.

The function becomes continuous.

The function is undefined and cannot be simplified.

The function is undefined but can be simplified.

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